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Aug 27 2020 02:53pm


I have a few questions not just looking for the direct answer.

What is the best way to approach a question like this ?
Do i need memorization of the periodic table to answer this question?
I just don't understand how to read the carbon skel.
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Aug 28 2020 01:05am
In this type of molecule you notice that you have C, H, O atoms

Such that a formula could be C(x)H(y)O(z), fill in how many atoms of each, and you get the chemical formula. SPOILER: In this case it would be C2H4O, of course you could write this various ways; but the most important feature is to identify how many atoms of each element the compound contains.
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Aug 28 2020 12:53pm
C2H4O

or more commonly

C2H3OH to denote the alcohol group

Common name is ethenol or vinyl alcohol

This post was edited by TheStealthTarget on Aug 28 2020 12:55pm
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Aug 28 2020 07:28pm
Quote (Illumini @ Aug 28 2020 03:05am)
In this type of molecule you notice that you have C, H, O atoms

Such that a formula could be C(x)H(y)O(z), fill in how many atoms of each, and you get the chemical formula. SPOILER: In this case it would be C2H4O, of course you could write this various ways; but the most important feature is to identify how many atoms of each element the compound contains.


Quote (TheStealthTarget @ Aug 28 2020 02:53pm)
C2H4O

or more commonly

C2H3OH to denote the alcohol group

Common name is ethenol or vinyl alcohol


thank you so much guys. i ended up practicing more structural formulas like benzene to grasp the idea. I'm clueless on this question if you guys can assist. I'm just confused to how you know what molecule is drawn? is it supposed to be known what is drawn ? Yes as you can see I'm struggling. I'm using all resources. I hate that my class including lab reports will be virtual, In-person lectures are really helpful. I guess this is the self learning stage.





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Aug 28 2020 08:29pm
Quote (Llove @ Aug 28 2020 08:28pm)
thank you so much guys. i ended up practicing more structural formulas like benzene to grasp the idea. I'm clueless on this question if you guys can assist. I'm just confused to how you know what molecule is drawn? is it supposed to be known what is drawn ? Yes as you can see I'm struggling. I'm using all resources. I hate that my class including lab reports will be virtual, In-person lectures are really helpful. I guess this is the self learning stage.

https://i.ibb.co/cyyztGc/Screen-Shot-2020-08-28-at-9-27-17-PM.png


Molecular formula = each atom and number.

Empirical formula = simplified ratio of atoms.

So C2H4O2 can be a molecular formula, but can never be an empirical formula because you can divide all the numbers by 2.

CH2O is the empirical formula for the above, but is also the molecular and empirical formula for formaldehyde.
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Aug 30 2020 12:07pm
Quote (Thor123422 @ Aug 28 2020 10:29pm)
Molecular formula = each atom and number.

Empirical formula = simplified ratio of atoms.

So C2H4O2 can be a molecular formula, but can never be an empirical formula because you can divide all the numbers by 2.

CH2O is the empirical formula for the above, but is also the molecular and empirical formula for formaldehyde.


:hug: really appreciate the help on the problems. could you tell me if i have the correct balanced formula ?




my answer .. 2NO(g) + O2(g) ----------> 2NO2(g)
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Aug 30 2020 12:10pm
Quote (Llove @ Aug 30 2020 01:07pm)
:hug: really appreciate the help on the problems. could you tell me if i have the correct balanced formula ?


https://i.ibb.co/8jCr0jK/Screen-Shot-2020-08-30-at-2-06-37-PM.png

my answer .. 2NO(g) + O2(g) ----------> 2NO2(g)


Yeah, it's balanced.

You can always tell if an equation is balanced just by adding up the atoms and charges on the left and right.

2 nitrogens, 4 oxygens left and right.

and charges of all species is zero so charges are balanced.

This post was edited by Thor123422 on Aug 30 2020 12:11pm
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Aug 30 2020 12:41pm
Quote (Thor123422 @ Aug 30 2020 02:10pm)
Yeah, it's balanced.

You can always tell if an equation is balanced just by adding up the atoms and charges on the left and right.

2 nitrogens, 4 oxygens left and right.

and charges of all species is zero so charges are balanced.


how about this one? i'm just confused on calculating the mass. as i know 1kg - 1000g. how would i approach this?

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Aug 30 2020 12:42pm
Quote (Llove @ Aug 30 2020 01:41pm)
how about this one? i'm just confused on calculating the mass. as i know 1kg - 1000g. how would i approach this?

https://i.ibb.co/pPG786T/Screen-Shot-2020-08-30-at-2-40-54-PM.png


Remember that one mole is 6.022x10 atoms.

And that a molecular weight is the mass of one mole of atoms.
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Aug 30 2020 01:44pm
Quote (Thor123422 @ Aug 30 2020 02:42pm)
Remember that one mole is 6.022x10^23 atoms.

And that a molecular weight is the mass of one mole of atoms.







could you tell me if this sounds right?

200 g/500 ml x 4= ?

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