d2jsp
Log InRegister
d2jsp Forums > Off-Topic > General Chat > Science, Technology & Nature > Physics Q (3 Parts: 100fg X 3) > Need Help Getting Answer.
Add Reply New Topic New Poll
Member
Posts: 3,680
Joined: Aug 5 2005
Gold: 23,037.68
Sep 24 2015 07:46pm
FT: 100fg x 3 (for all 3 parts)

I need help with a Physics Q due Sunday..



Paying 100fg for each part! :D

If u kno where to get Physics Web Assign "pathways" to solutions or something.. LMK. I'm interested.

The book is college physics..

&& b/c I lived the life with a MCSE man in 2005 during his PC BANG business for his lil bro.. I will just ask.. The one thing I want is the test bank.. for my college physics course. LMK your price.. PM or post.. thanks..T_T

Man.. I should've took Chemistry.. It was PHYSICS class that took me out of highschool when I was a senior too.. T_T
Member
Posts: 13,222
Joined: Jan 2 2011
Gold: 17,400.00
Sep 26 2015 11:11am
probably post this in homework section might get help quicker
Member
Posts: 3,328
Joined: Jun 7 2015
Gold: 64,181.51
Sep 27 2015 02:50pm
i might be too late, but i somehow stumbled on this sub forum haha.

for A, you need to know the elasticity constant of the pole ( i don't have access to these constants,but it's just half of hardwood according to the problem).

the downward force is simply Tcos(30*) + Tcos(80*). you can ignore the 3rd force that's perpendicular to the pole.

Now that you have the force in newtons, you can calculate pressure (P = F/A).

Now you can calculate the strain with strain = pressure/young's modulus.

Member
Posts: 3,328
Joined: Jun 7 2015
Gold: 64,181.51
Sep 27 2015 02:53pm
B is the same concept, except you care about tangential forces.

So here the total sideways force = Tcos(90) + Tsin(30) + Tsin(80).

Here, I assume the shearing force is applied to the cross sectional area of the pole, so the area here is the same as in A.

Now, strain = force/shearing modulus (another constant that you just gotta look up for this problem).

Member
Posts: 3,328
Joined: Jun 7 2015
Gold: 64,181.51
Sep 27 2015 02:57pm
C's a neat one.

you basically take your force in the X direction, and divide by cos(30), call this Fx. Take force in Y direction and divide by sin(30), call this Fy. The total tension should be sqrt(Fx^2+Fy^2).

It's quite a few years since i've studied engineering, so hopefully this is somewhat useful
Member
Posts: 57,755
Joined: Mar 7 2006
Gold: 0.00
Sep 28 2015 11:25am
gg
Member
Posts: 3,680
Joined: Aug 5 2005
Gold: 23,037.68
Oct 4 2015 05:50pm
Thank you for your answer jianstein! Sending 300fg ur way ^_^

to jiangstein (67,976.76 -> 68,276.76)

This post was edited by JamesTKD on Oct 4 2015 05:51pm
Go Back To Science, Technology & Nature Topic List
Add Reply New Topic New Poll