posting trick questions is rude.

I choose to weight my random distribution such that I can choose C in a non-paradoxical manner.

Suck on that, attempted paradox.

Why are A and D the same choices?

1 out of 4 at random is 25%. it doesn't matter what the answers are because you are picking at random.

With 3 choices, it would have been about 33.3%...
I vote that this is a trick question. If A and D are correct, it would be a 50% chance, so there is no correct choice that is given to answer. It lists 50%, too, to be worse?

This post was edited by L4d on Nov 2 2011 04:17am

you still aren't getting it. random means the data in each choice doesn't matter.
its asking if you are given 4 choices and you choose 1 at random what % chance you have of being right.

NOT

which one of the answers below is correct

I never knew what the question was asking, and I played "Devil's Advocate".

This post was edited by L4d on Nov 2 2011 04:21am

A/D

ACDC?!

It's ACDC isn't it?

Meh.
This statement is false.