can someone give me a worked answer, answering this (showing working out)

Calculate the amount, in mol, of solute present in:

20.00 mL of 0.255 M KOH Solution

2.50 L of 1.05 sucrose (C12H22O11)

inb4taketohomework
I don't have to do this, it's extension work and I would like to understand how to work it out; there is no working out(s) in the book.

This post was edited by rathianreborn on May 8 2011 05:14am

this is a basic unit conversion

molarity is in units of moles per liter.

mole / liter * liter of solution = mole of solution

I have the answer, but can you do 1 to prove this is right.

moles = concentration*volume

20/1000*0.255 = 0.0051 moles

2.5*1.05 = 2.625 moles

concentration is moles per litre and volume needs to be in litres