As you know, When two people synch two clocks and one person with a clock flies( C ) in a plane and lands, The person that flies has a slower time than the man sitting still( B ).
What if you add a third observer?
A: Relative to the Universe.
B: Relative to the Earth.
C: Flying in a plane on the Earth.
All three have synched clocks before movement.

Then Earth Moves at 10 units per second away from A.
C flies away from B but towards A at 2 units per second.
So C is moving 8 units per second away from A.

With that, B has the slowest time relative to A, but we already stated that C has a slower time an B.
How are B and C clocks slower than eachother?

At what speed is this person "flying"?

This post was edited by Jazz_Thing on Oct 4 2009 09:10am

"C flies away from B but towards A at 2 units per second.
So C is moving 8 units per second away from A."

Bump.

No one?

Ah, a fine question.

The true question arising out of this question that has yet to be answered is the real definitive answer.

What happens when you add my Dick and your mom into this equation?

The problem is your logic is broken, Time Dilation can only be measured as a relationship between two observers.. But there is still no scientific breakdown of the event your are describing it is just C clock is "slowest", A clock is reading in sync with the "original time" and B clock is in between the two because it has velocity, but not as much as C clock.

I know, only two observers. Thats why i asked what would happen if there were a third. You say C is the slowest, but B is moving the fastest from A. So from observer A, B would be the slowest.
Thanks for the reply.

This post was edited by AlphaPlus on Oct 5 2009 10:08pm

iso answer still.

it has nothing to do with what direction they are travelling (toward or away from each other doesnt matter). the thing to get here is the faster you are moving the slower time elapses on board the craft. after the journey when you compare time stamps you see the difference.