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Apr 29 2009 06:27am
i have a few hardcore chem qs that need answering plllz hellp!
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Apr 29 2009 03:16pm
How hard?
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Apr 29 2009 05:57pm
Quote (PTRH @ Wed, Apr 29 2009, 02:16pm)
How hard?


gay police offer at anal jail inspection hard
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Apr 29 2009 06:02pm
that hard ^^ can anyone help?
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Apr 29 2009 06:16pm
Quote (razbagz @ Thu, Apr 30 2009, 12:02am)
that hard ^^ can anyone help?


you can just post it...I don't understand why people do this... just post your damn work and someone who thinks they know it will just drop by and help you. PM'ing you is inconvenient...I personally wouldn't go out of my way to PM you, about YOUR homework even though I know my chem.

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Apr 29 2009 06:45pm
ok then..

1) Helium balloons are used to carry scientific instruments high into the atmosphere. Suppose
that such a balloon is launched on a summer day when the temperature at ground level is
22.5°C and the barometer reading is 754 mm Hg. If the balloon’s volume is 1.00 x 106 L at
launch, what will the volume be (in litres) at a height of 37 km, where the pressure is 76.0 mm
Hg and the temperature is 240.0 K?


2) Helium balloons reach high altitudes because the gas density is far less than the density of
the atmosphere (~1.18 kg m-3 at ground level). Calculate the density (in units of kg m-3) of the
helium gas in the balloon described above at 22.5°C and 754 mm Hg.
Answer
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Apr 29 2009 07:17pm
Quote (razbagz @ Thu, Apr 30 2009, 12:45am)
ok then..

1) Helium balloons are used to carry scientific instruments high into the atmosphere. Suppose
that such a balloon is launched on a summer day when the temperature at ground level is
22.5°C and the barometer reading is 754 mm Hg. If the balloon’s volume is 1.00 x 106 L at
launch, what will the volume be (in litres) at a height of 37 km, where the pressure is 76.0 mm
Hg and the temperature is 240.0 K?

PV = nRT, they give you one scenario where T = 22.5 C = 295.5K, V = 1*10^6 L, P = 754 mmHg = .992 atm, and you know R = 0.0821 (I think, its been a while for me). So plug all the info that they give you, into PV = nRT, where n is the unknown and you should get n = 40889.42 moles (thus we now know that this balloon contains so many moles of helium in it)

Now they ask what the VOLUME will be at this new height, so again, using PV = nRT we will solve it. List the givens, P = 76 mmHg = .1atm, T = 240K, n = 40889.42 (as we found out), and R = .0821. So plug your info in, and you should get that volume = 8056851.317 L



2) Helium balloons reach high altitudes because the gas density is far less than the density of
the atmosphere (~1.18 kg m-3 at ground level). Calculate the density (in units of kg m-3) of the
helium gas in the balloon described above at 22.5°C and 754 mm Hg.
Answer

We know that density = mass/volume, mass = (moles * atomic mass of helium = 40889.42 * 4.002 = 163639.49 GRAMS ) [and be careful here, they want mass in KILOGRAMS, not grams, so divide the answer you get for mass by 1000, so mass = 163.639 Kg]. We found out that the volume = 8056851.317 L , but they want the answer in CUBIC METERS, so if you remember, 1 cubic meter = 1000 liters, so your volume = 8056.851 cubic meters of helium.

Now just go back to our original formula, D = M / V = 163.639 / 8056.851 = .02031 kg m^-3


This just requires some thinking, these questions aren't tough, maybe you should review your fundamentals because chemistry questions can get A LOT tougher than this.

Edit: Didn't bother using significant figures for this, so if your teacher requires that, just do it over again using sig figs. Sorry about that (I don't do chem anymore, so I fell out of the practice of using sig figs)

This post was edited by BovineDesi on Apr 29 2009 07:19pm
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Apr 29 2009 07:49pm
im a geology student in my graduate year...because i started mid term i have to finish these crappy fundamental units..ill never use this stuff again. thanks for the help.
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Apr 29 2009 08:01pm
Quote (razbagz @ Thu, Apr 30 2009, 01:49am)
im a geology student in my graduate year...because i started mid term i have to finish these crappy fundamental units..ill never use this stuff again. thanks for the help.


I'd assume a geologist would have to know a fair amount of chemistry, at least mineral chemistry right?
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Apr 29 2009 08:07pm
lol valence charges, this helps in determining the compatable elements within a particular rock and is good evidence of the petrogenesis (orgin and evolution) of a magmatic source.
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