so in a lock for boats and stuff, is the pressure at the bottom of the water higher when there is a boat above it?


like, if a us battleship went into a lock, would the pressure on the bottom go up? and what would be the relation to the mass added above? (if any)


the boat displaces the water equal to its weight right?

Archimedes's principle says the amount of water displaced is equivalent to the SIZE of the object. However I don't know too much about the pressure, but taking an educated guess (okay really its just a guess), I'd say water pressure wouldn't change since the boat doesn't PUSH any water down (it displaces it like you said) and the surface of the water exerts a force equal to the weight of the boat to keep it afloat (omg rhymes!)...but like I said, I'm probably wrong since that was just a guess.

ya but that would only apply if the boat wasn't a boat, and it was a submarine and went completely under water, then it would displace water equal to its volume

Well for the boat wouldn't it just be the size of the hull that's submerged in water?

and to get the volume of submerged hull it's just 1 litre per kilogram the boat weighs
way to try to be smart with your archimedes principle

and pressure won't change

what?

the more the boat weighs the more water it will displace

(like when you overload a canoe, if you put more weight in it it goes down in the water more

i think it can be calculated with the weight of water?

simply put... no. pressure on the bottom wont go up

hmmm... water in the ocean causes pressure changes depending on the depth 14.7psi per 33 feet or something like that. isn't that pressure difference only because of the weight of the water on top of it?

Well the water would be colder (denser) & you would be closer to the center of the earth (more gravity). I would not know the relation with the amount of water.