Stop arguing, you're wrong (surprise). If you don't even know that * is a multiplication symbol then how can you possibly have the nerve to argue with me?

Putting two characters next to each other (for example "xy" or "πr" or "r2") or putting a multiplication symbol in between them (for example "x*y") are both notations that mean to multiply them.

No, just putting a 2 after something does not mean squared because you've made no designation that you're raising to the power of 2. You can write either πr^2 to designate a superscript/power, for the area of a circle (which is not πr2, more commonly written 2πr which is the circumference of a circle), or use the actual superscript character like πr². You cannot write πr2 because that is literally a different mathematical statement.

This post was edited by Voyaging on Mar 11 2016 07:44pm

The Hubble 'constant' is about 68 km*Mpc/s meaning a galaxy 1 Mpc away is receding at 68 km/s. So

Mpc = 3*10^19 km
RV = recession velocity (km/s)
D = distance to galaxy (km)
gives us:
RV = 68*D/(3*10^19) km/s

So lets say we want a recession velocity of 100% light speed: RV = 300,000 km/s = 3*10^5 km/s

3*10^5*3*10^19/(6.8*10^1) = D

D ≈ 1.3 * 10^23 km

a light year is about 10^13 km so thats a distance of about 1.3 * 10^10 light years or about 13 billion light years. Anything further away than that will be receding at faster than light speed.

That isn't what you used though.

That is exactly right.

google it, your assumptions are completely asinine, if I just said r2 then it could be assumed I meant r *2 but if we are talking about area and I say πr2, its pi r squared. Heres an idea - why don't you go and correct the 274,000 times it has been used on the internet and tell them that they are all wrong, because of your assumptions.

yes it is, look up my post - you were the one who suggested my referring to avg equator temperature at noon was somehow just avg temperature, you're conflating the two distinct ideas is probably a representation of other problems.

the temperature you used for Mars is the high, not the average. The temperature you posted for the Earth (while I don't know if it is correct) is clearly NOT the high (since much higher temperatures are in the common experience). Apples and oranges.

And this still does not address your use of the Fahrenheit scale to set up a proportion equation.

Think about it:

Is the solar energy required to heat an object to 2 degrees F twice as much as the solar energy required to heat an object to 1 degree F? No way, but that is the argument you made...

I looked up average temperature of the equator on Mars at noon , two different sites told me it was 70- 80 degrees, this is an average temperature, not a high. Maybe you assumed it was a high, maybe because your high? IDK, where do you get these assumptions from - I say one thing and you assume another - thats pretty fuked up language comprehension.

1 degree difference = 2x the solar power? - nice assumption - did i ever say that - I love how you just make up wild and wilder assumptions, hilarious.
you are really desperate to demonize me, that is pretty unquestionable.
Do you understand there is a difference between the words I actually type and some idea in your head?

This post was edited by card_sultan on Mar 11 2016 08:34pm