.999 = 1 - Topic

chiefwiggum654

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#41

Apr 20 2009 11:34am

Quote (BovineDesi @ Mon, Apr 20 2009, 09:06am)

Haha, actually a quick riddle, figure out how I'm making 2=1:

1^2 = 1 ..................(1 times)
2^2 = 2 + 2 .............(2 times)
3^2 = 3 + 3 + 3 ........(3 times)
4^2 = 4 + 4 + 4 + 4 ...(4 times)
so,
x^2 = x + x + x + x....(x times)

Now if we take the derivative of both sides, we get
2x = 1 + 1 + 1 + 1... (x times)
therefore, 2x = x, then 2(x/x) = 1 so 2 = 1.

Right? :D, actually the answers really easy but its some brain fodder

wat

BovineDesi

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#42

Apr 20 2009 11:40am

Quote (chiefwiggum654 @ Mon, Apr 20 2009, 05:34pm)

wat

Nope, that part is perfectly logical. That is not wrong to say.

chiefwiggum654

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#43

Apr 20 2009 01:06pm

Quote (BovineDesi @ Mon, Apr 20 2009, 10:40am)

Nope, that part is perfectly logical. That is not wrong to say.

Yeah, I dunno what I was thinking. I haven't been exposed to a even slightly difficult math for about a year now, so I'm pretty rusty.

Dr_Grignard71

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#44

Apr 20 2009 01:39pm

x^2=x+x+x...

doesn't work for zero

also, when you reach

2x=x

you can't divide out the x, because you're eliminating zero as an answer

i don't know whether there's a connection between the two

This post was edited by Dr_Grignard71 on Apr 20 2009 01:44pm

BovineDesi

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#45

Apr 20 2009 02:14pm

Quote (Dr_Grignard71 @ Mon, Apr 20 2009, 07:39pm)

x^2=x+x+x...

doesn't work for zero

It does work for zero, 0^2 = 0+0+0 (technically zero times, but its not wrong)

also, when you reach

2x=x

you can't divide out the x, because you're eliminating zero as an answer

mm... part of the answer, but you're not encompassing the entire reason why this doesn't work

i don't know whether there's a connection between the two

I'll give you guys a hint, graph both sides of the equal sign

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#46

Apr 20 2009 03:05pm

for some reason i thought 0^0

BovineDesi

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#47

Apr 20 2009 06:21pm

Quote (Dr_Grignard71 @ Mon, Apr 20 2009, 09:05pm)

for some reason i thought 0^0

yea simple brain farts...happens to me too, anyways, the answer is that x + x + x + x (x times) is not a continuous, and therefore not a differentiable function. x + x + x + x are not variables anymore, they become real numbers, and the derivative of real numbers always equals 0, not 1

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#48

Apr 20 2009 09:12pm

how is that not continuous?

This post was edited by Dr_Grignard71 on Apr 20 2009 09:12pm

RageMastaFlex

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#49

Apr 21 2009 09:29am

Quote (BovineDesi @ Mon, Apr 20 2009, 08:18am)

No....where do you see me dividing by zero here, I'm not dividing anything by zero.

... well with your thing I was tired and never took the time to read fully, but in the usual algebraic expression to make 1=2 everything works out except they try to divide by zero and make you not notice it...

however with imaginary numbers, you can.

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#50

Apr 21 2009 09:42am

Quote (Dr_Grignard71 @ Tue, Apr 21 2009, 03:12am)

how is that not continuous?

x + x + x + x isn't even a function, its a plot of real numbers because x is not a variable. X^2 has varying x values, while on the other side of the equal sign, x + x + x + x etc... are just constants. You can't differentiate that.

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