a 3 pound weight is not analogous to an unstoable force, and a wall that can take 3 pounds of force is not analogous to a immovable wall.

your calculations infer that the un stopable force is stopable, and if the unstopable force is stopable then it never was an unstopable force.

personally id go with every action has an equal and opposite reaction, at impact the force channels its force back into itself in the opposite vector.

This post was edited by Ylem122 on Sep 13 2012 02:45am

He never said the collision is elastic.

an elastic colission would infer that energy is lost in the elasticity, if anything my statement infers that there is 0 elasticity.

similar to one of these things:



or like what happens when a karate guy trys to chops a peice of wood inhalf and fails, the energy returns to your hand instead of being used to break the board.

This post was edited by Ylem122 on Sep 13 2012 02:50am

why am i the only one to see that unstoppable in no way implies contact with anything ?

if its a wall that isnt moveable... and its in the path of an unstopable force...

the force probably goes through the wall... because the wall isnt unbreakable or unmeltable..

This is a very good answer..


You need to be more specific about what is the wall made of, and its size etc.. as well as the force, what shape is this force? And whats its mass, velocity, whats it made of, etc..


Your question (even being scientific) its vague (full of possibilities), and its a dumb question (yes scientists who ask it are dumb).

how exactly does breaking it or melting it not move it?

cause it goes into warp space

This post was edited by the_rest on Sep 13 2012 03:03pm

the universe implodes from the absurd amount of retarded questions based outside of reality.

No, elasticity prevents energy from being lost. A perfectly elastic collision would mean that all of the energy gone into the collision would be used perfectly efficiently, which would mean that the kinetic energy would not be lost. Your statement assumes perfect elasticity.