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Jan 4 2009 04:30pm
Quote (Garethsir @ Sun, Jan 4 2009, 08:13pm)
the more the boat weighs the more water it will displace

(like when you overload a canoe, if you put more weight in it it goes down in the water more

i think it can be calculated with the weight of water?


If it weighs more it just means more of the canoe submerges under the water (so its still the size/mass of the object that is equivalent to the amount of water displacement). Weight is an indirect way to say it.
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Jan 4 2009 07:16pm
Quote (LouisLeGros @ Sun, Jan 4 2009, 10:27pm)
Well the water would be colder (denser) & you would be closer to the center of the earth (more gravity). I would not know the relation with the amount of water.


what about thermal vents? water near thermal vents on the ocean floor can be over the boiling point (100 degrees C) and still remain a liquid because of the pressure
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Jan 4 2009 07:23pm
Quote (Garethsir @ Mon, Jan 5 2009, 01:16am)
what about thermal vents? water near thermal vents on the ocean floor can be over the boiling point (100 degrees C) and still remain a liquid because of the pressure


You guys are both going off topic here, the question is whether pressure changes, so if there were thermal vents so what? AFTER you place the boat on that column of water, does the pressure 'change' and I think it was a unanimous no tongue.gif
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Jan 4 2009 07:31pm
you might of said no, but you didn't back it up with anything?
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Jan 4 2009 07:52pm
Quote (Garethsir @ Mon, Jan 5 2009, 01:31am)
you might of said no, but you didn't back it up with anything?


I'm pretty sure a couple other people said no

edit: but ur right mine was just an intuitive guess based on what i know.

This post was edited by BovineDesi on Jan 4 2009 07:52pm
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Jan 4 2009 07:56pm
Quote (Garethsir @ Sun, 4 Jan 2009, 17:16)
what about thermal vents? water near thermal vents on the ocean floor can be over the boiling point (100 degrees C) and still remain a liquid because of the pressure


Second sentence said I didn't know how the relation works.


where,
P is the hydrostatic pressure (Pa);
ρ is the liquid density (kg/m3);
g is gravitational acceleration (m/s2);
h is the height of liquid above (m);
Pa is the atmospheric pressure (Pa).

and I guess the relation would be the product of the other 2 things I mentioned (plus atmospheric pressure).


Given that I would imagine in a situation like a lock the pressure would be greater given that the water remains constant (larger ship will displace more water, increasing the height of the liquid above where you would be measuring water pressure).

I don't know enough about the way locks work to be able to give an answer for the initial question. If it were just in the ocean I would imagine that the change would be negligible.
It would be a great question for my physics professor to answer... too bad I'm not taking physics this quarter.


This post was edited by LouisLeGros on Jan 4 2009 07:59pm
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Jan 12 2009 08:48am
Right.
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