Quote (juicetoocool17 @ Nov 12 2014 11:39pm)
Well first question is which field is this? You mentioned math but the base is not written so in CS we would assume 2, math 10 or sometimes e, etc. Which is it? If it's 10.
figure out which base is being used by wolfram by doing log(e) and log(2) and log(10), see which one gives you 1. I'd guess they use the e base. Then plug in the change of base forumula if you need it? Assuming it's 10, you don't.
Assuming 10, quickly I believe it's 10^8.
log_10(10^2)=log_10(100)=2.
So 10^(4*2))=10^8
it's log base 10, if you look at the picture.
hint @ op: since 10 is both the base of the exponential and the base of the logarithm (if you paid attention to the link i posted), you can safely substitute 10 in both places for n and solve it accordingly so it doesnt distract you. or in my case i prefer e:
n^(4*log_n(2))
or my preference:
e^(4*ln(2))
does that make it simpler for you?
This post was edited by carteblanche on Nov 12 2014 10:45pm