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Jul 25 2016 11:46am
p=1-(.4)^12
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Jul 25 2016 11:48am
% to train vs % to rain
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Jul 25 2016 11:50am
Quote (Nathan @ Jul 25 2016 06:46pm)
p=1-(.4)^12


this
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Jul 25 2016 12:13pm
Quote (Si7c @ Jul 25 2016 12:23pm)
The idea is: if it doesn't rain the first hour (60% chance) it might rain the second hour (60%), or the third (60% chance), etc for 12 hours.

It will obviously be pretty high, but idk the equation


ah i see now,
the wording of the question was a bit confusing
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Jul 25 2016 12:23pm
Quote (RzChaos @ 25 Jul 2016 09:16)
The problem statement is too ambiguous.

Is it a 60% chance that all 12 hours contain rain, or is there a 60% chance of rain for each individual hour in the next 12 hours.


I thought this too, but figured I'd go with the obvious interpretation
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Jul 25 2016 12:36pm
Quote (RzChaos @ Jul 25 2016 09:16)
The problem statement is too ambiguous.

Is it a 60% chance that all 12 hours contain rain, or is there a 60% chance of rain for each individual hour in the next 12 hours.


Quote (Si7c @ Jul 25 2016 05:06pm)
For the next 12 hours there is a 60% chance to train every hour.

What is the chance that it rains at any point during those 12 hours?

/E I need an equation :)

if you read it the other way it would say
there is a 60% chance of rain over the next 12 hours
whatis the chance of rain over the next 12 hours

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Jul 25 2016 12:41pm
Ill defined question


At any point in time it will start raining? Basically zero.
Be raining at any point in time? Not determinable.
Start raining during any one-hour interval? This can actually be answered I think.
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Jul 25 2016 12:43pm
Quote (AiNedeSpelCzech @ 25 Jul 2016 08:12)
assuming you're taking each as a discrete 'roll'


This is why I clarified with this in post #5 which OP confirmed, glad that we're all parsing something that was handled at the beginning of thread. :P
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Jul 25 2016 02:39pm
720% chance of rain hit me up if you need more math help
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Jul 25 2016 02:43pm
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