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> Need Help > Algebra 7-8klass Lol
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partypoker
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#1
Feb 23 2010 04:23pm
[5x-3/3*(x+2)] - (x+3/x+2)
ya znau otvet, no ne mogu k nemu prijti
znau, smeshno, no eta xujnya mne pokoya ne daet xD
kto mojet podrobno raspisat' reshenie pls?
Apocalypticus
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#2
Feb 23 2010 04:42pm
х=любое число, судя по твоей записи
даже решать не надо
This post was edited by Apocalypticus on Feb 23 2010 04:42pm
Fabulous
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#3
Feb 23 2010 04:43pm
а в чем вопрос-то? и что требуется решить?
This post was edited by Sfairat on Feb 23 2010 04:44pm
Doksait
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#4
Feb 23 2010 04:44pm
я этой хуйнёй в учаге намаялся ))) даже вспоминать страшно
partypoker
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#5
Feb 23 2010 04:44pm
blin ya imell vvidu sokratit'
dimon222
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#6
Feb 23 2010 04:48pm
Quote (partypoker @ 24 Feb 2010 01:44)
blin ya imell vvidu sokratit'
lol?
Doksait
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#7
Feb 23 2010 04:50pm
Quote (partypoker @ 24 Feb 2010 01:23)
[5x-3/3*(x+2)] - (x+3/x+2)
ya znau otvet, no ne mogu k nemu prijti
znau, smeshno, no eta xujnya mne pokoya ne daet xD
kto mojet podrobno raspisat' reshenie pls?
Будет 40 градусов )))
partypoker
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#8
Feb 23 2010 04:50pm
Quote (dimon222 @ 23 Feb 2010 23:48)
lol?
^^
Fabulous
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#9
Feb 23 2010 04:51pm
(5x-3)/[3*(x+2)] - (x+3/x+2) = (5x-3)/[3*(x+2)] - 3*(x+3)/[3*(x+2)] = (5x-3-3x-9)/[3*(x+2)] = (2x-12)/[3*(x+2)]
что может быть проще?
я сначала подумал, что это уравнение или неравенство какое-то
This post was edited by Sfairat on Feb 23 2010 04:51pm
dimon222
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#10
Feb 23 2010 04:51pm
Quote (partypoker @ 24 Feb 2010 01:50)
^^
Квадратные скобки какое значение играют в твоём примере?
Quote (Sfairat @ 24 Feb 2010 01:51)
(5x-3)/[3*(x+2)] - (x+3/x+2) = (5x-3)/[3*(x+2)] - 3*(x+3)/[3*(x+2)] = (5x-3-3x-9)/[3*(x+2)] = (2x-12)/[3*(x+2)]
что может быть проще?
Если квадратные скобки это тупо скобки то да, но если это... хм
This post was edited by dimon222 on Feb 23 2010 04:52pm
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