n is an integer above 1
m is an integer above 1

n^(m-1)=n^(m-1)

I can do the prove for any m, but n is then fixed Like n=2.

How can I induce two variables at the same time?

First to not help

Shit thread.

just set n = x

You can't induce over two independent variables in the usual sense unless your proposition is defined over a grid of values and can be reduced step by step using a well-order (like lexicographical order).

So the correct approach is not to try a double induction, but rather to analyze and solve the equation for which pairs it holds.

Second to be first to not help.

Thanks for your explanation.
It was a fools Quest because I oversaw n^m=n^(m-1)+n
Which by Chance Looks like more

But 10 years after my failed university try I finally have the time for learning. Not Just solving as I am tasked...

it was the last paragraph from my chatgtp after 2 pages of text and numbers!

Gg wp

Looks like the homework section can finally be put to use

https://forums.d2jsp.org/forum.php?f=257