we know cos = 0 when its pi/2 , 3pi/2, 5pi/2

etc...

so can we say, cos [(2n-1) * pi/2] = 0 ?

ya that works as long as u say n is an integer

yea n is an integer... but does

(2n+1) * pi/2 work or does it depend on what "n" u start with?

This post was edited by FamilyGuyViewer on Nov 26 2016 10:07pm

(2n+1) * pi/2 works the same as (2n-1) * pi/2 if ur considering n to be any possible integer

Damn familyguyviewer back at it again with the homework requests

yes I know but it depends on which "n" u start with, like zero or 1.

if I start at n = 0, then its 2n+1 * pi/2

otherwise n=1 is 2n-1 * pi/2

As long as you are taking the cosine of odd multiples of pi/2, it will be 0 regardless of a positive or negative argument.

This is just a way of saying 0
for odd numbers its just n=1,3,5...

This post was edited by Squaunch on Dec 19 2016 09:09am