I'm a complete garbage regarding to Math and I have this problem I should help her with.
If some1 has a solution, it'd be cool. !

Solved Example:
1) X2-4X+3
2) (x-3)(x-1)

Need Help With:
1) 6x2-6x-36
2) ???


(bolded 2's are Squared)

(2x-6)(3x+6)

pretty sure

I tested it and it's ok, thanks.
What's the process in getting to that result? I can't seem to remember it, was so long ago since I've done it back in high school

6X² - 6X - 36

Notice that 6 is a common factor :

6 * ( X² - X - 6)

Quadratics of the form aX² + bX + c can be factored using the discrimant D = b² - 4*a*c

In your case : D = (-1)² - 4 * 1 * (-6) = 1 + 24 = 25 = 5²

Roots are (real roots if D is positive or equals zero) :
X₁ = ( - b - √D ) / (2*a) and X₂ = ( - b + √D ) / (2*a)

Here :
X₁ = ( -(-1) - 5 ) / (2*1) = -2
X₂ = ( -(-1) + 5 ) / (2*1) = 3

Factorisation : a * (X - X₁) * (X - X₂)

Here : 1 * ( X - (-2) ) * ( X - 3) = (X+2)(X-3)

Conclusion :
6X² - 6X - 36 = 6(X+2)(X-3)

this

http://forums.d2jsp.org/topic.php?t=75151420&f=115&p=508574002

Thanks.
Now she's crying. She's even more confused.

I just wanted to be a good brother, now I'm an asshole.




Thanks for your effort tho, I'll try to explain it to her in a common toungue !

i can try to explain in common tongue

once you factor out the 6 you're left with x^2-x-6
the middle term (happens to be -x here) is going to be the SUM of the two integers (-3 and positivee 2) and the third term(-6) is going to be the product of the two integers

so when you're trying to determine the two integers i always look at the third term and find all the common multiples. theres only 2 here 1x6 and 2x3.
you know its 2x3 immediately because 2-3 will give you the -1 that you need the middle term to be

This post was edited by aDamNerd on Oct 19 2016 01:17pm