Anyone Know How To Integrate This Disgusting - Topic

FamilyGuyViewer

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Sep 25 2016 12:17pm

integrate u'1 with respect to x

is this even possible..

FamilyGuyViewer

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Sep 25 2016 12:58pm

sooo I tried it on Matlab

Code

syms x
int((exp(3*x)*(x^2)*(x+1)^2 - 3*(x^2)*exp(2*x)*cos(x))/(exp(3*x)*(x^2+x+1)),x)

and heres the output...

Code

ans =

-int((exp(-3*x)*(3*x^2*exp(2*x)*cos(x) - x^2*exp(3*x)*(x + 1)^2))/(x^2 + x + 1), x)

why did it give an integral in the output??

eLeMeNt477

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Sep 25 2016 01:27pm

Define the function as an anonymous function

FamilyGuyViewer

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Sep 25 2016 04:57pm

Quote (eLeMeNt477 @ Sep 25 2016 02:27pm)

Define the function as an anonymous function

how

eLeMeNt477

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Sep 25 2016 05:53pm

Quote (FamilyGuyViewer @ Sep 25 2016 06:57pm)

how

google it

FaceDeath

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Sep 25 2016 06:02pm

pm xyzamp
he can Integrate This Disgusting > Function np

FamilyGuyViewer

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Sep 25 2016 06:39pm

Quote (eLeMeNt477 @ Sep 25 2016 06:53pm)

google it

tried didnt work

eLeMeNt477

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Sep 25 2016 06:42pm

Quote (FamilyGuyViewer @ Sep 25 2016 08:39pm)

tried didnt work

https://www.mathworks.com/help/matlab/matlab_prog/anonymous-functions.html

maruthenoob

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Oct 7 2016 05:20am

Would you mind posting the entire assignment?

Are you solving this ODE with the method of undetermined coefficients?

Oh my gosh sorry for bumping a 2 week old post zz.

This post was edited by maruthenoob on Oct 7 2016 05:27am

ringo794

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#10

Oct 7 2016 10:36am

hmmm
it can be broken into a number of terms including products and quotients
breaking it up into easier to deal with terms might help, or maybe it wont
don't feel like looking into this because even if it isn't hard it's gonna take a while

the e^3x would totally disappear in one term, and stay as an e^x in the denominator in another
that would simplify things a bit. other simplifications with the polynomial are possible as well

This post was edited by ringo794 on Oct 7 2016 10:38am

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