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Sep 11 2016 06:49pm



Find the real solutions of the equation.

8x^4-2x^2-1=0
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Sep 11 2016 06:52pm
first step is to factor.

8x^4-2x^2-1=0
(4x^2+1)(2x^2-1) = 0

set each piece to 0.
(4x^2+1) = 0
(2x^2-1) = 0

i assume you can take it from here
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Sep 11 2016 06:54pm
(2x^2 - 1)(4x^2 + 1) = 0

x^2 = 1/2 --> x = sqrt(1/2)
x^2 = -1/4 ---> reject, not real

This post was edited by FamilyGuyViewer on Sep 11 2016 06:55pm
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Sep 11 2016 07:52pm
thanks, i got it now, you all are the best!
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Sep 12 2016 12:55am
Quote (FamilyGuyViewer @ Sep 12 2016 01:54am)
(2x^2 - 1)(4x^2 + 1) = 0

x^2 = 1/2 --> x = sqrt(1/2)
x^2 = -1/4 ---> reject, not real


Well played answering a question below your level that had already been answered
Now evr1 noes u smaert
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Sep 12 2016 10:49pm
Quote (FaceDeath @ Sep 12 2016 01:55am)
Well played answering a question below your level that had already been answered
Now evr1 noes u smaert


its sad how ur constantly lurking around this forum for constant attention
"Pm xyzamp
He can do this"

the first few topics on this page are all last replies by you rofl, get a life
Member
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Sep 13 2016 05:53am
Quote (FamilyGuyViewer @ Sep 13 2016 05:49am)
its sad how ur constantly lurking around this forum for constant attention
"Pm xyzamp
He can do this"

the first few topics on this page are all last replies by you rofl, get a life


im crying irl
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