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Mar 9 2016 01:35pm
i need help with number 9 will pay fg for answer



This post was edited by dizzle19 on Mar 9 2016 01:37pm
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Mar 9 2016 02:41pm
any 1 :O
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Mar 9 2016 02:53pm
x = 105°

Let O the center of the circle.

COB = 90°
hence, CAB = 45°

DOA = 140°
hence, DBA = 70°

In the triangle EAB, angles are 45° , 70° and AEB, hence, AEB = 75°.

AEB + x is a flat angle :
x = 180° - 75°
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Mar 10 2016 10:56am
Quote (feanur @ Mar 9 2016 01:53pm)
x = 105°

Let O the center of the circle.

COB = 90°
hence, CAB = 45°

DOA = 140°
hence, DBA = 70°

In the triangle EAB, angles are 45° , 70° and AEB, hence, AEB = 75°.

AEB + x is a flat angle :
x = 180° - 75°


Thank you!
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Posts: 16,662
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Mar 10 2016 11:39am
And ooops, I made a mistake at the final :

AEB = 65° (of course) and x = 115°

Sorry for that...
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