Quote (feanur @ Mar 9 2016 01:53pm)
x = 105°
Let O the center of the circle.
COB = 90°
hence, CAB = 45°
DOA = 140°
hence, DBA = 70°
In the triangle EAB, angles are 45° , 70° and AEB, hence, AEB = 75°.
AEB + x is a flat angle :
x = 180° - 75°
Thank you!