outer dimension of frame is 40in by 32in

are within frame is 10in^2

what is width of frame

must show work

----------
long division

(12x^3 - 29x^2 - 14x + 16) / (3x-8)



25 fg each

pming me would be best, first correct w/ work gets fg

That area within the frame is tiny compared to the frame dimensions. Are you sure that's the correct problem?

either way, the setup is:
(40 - x) * (32 - x) = 10

shouldn't it be (40 - 2x) * (32 - 2x) = 10 ?

But yeah, that would lead to a very weird frame.

yeah i'm sure

if you could continue to solve you win

still need help

expand it, it will lead to a quadratic equation, use the quadratic formula

Here I worked them out on paper, easier than typing out.





This post was edited by timmayX on Feb 22 2016 12:51am