solve syst3m of linear equa1i0n using matrice3s

6x-2y=-7
4x+3y=17

need to show work getting it into row echelon form and then solving

30 fg for first person to do it

which step are you having a problem with?

well my row operations went like R1=r1/6, to get 1 in the first row, first colomn

then R2=-4r1+r2 to get 0 below 1, which i think may have been getting too far ahead of myself because after that things got messy

you were on the right track. dont be afraid of fractions.

here's a site that works it out for you:
http://www.math.odu.edu/~bogacki/cgi-bin/lat.cgi

ok found a minor mistake i made


if someone could just tell me what the get for x and y, and if its correct they will win

This post was edited by KINGSTANNIS on Feb 14 2016 07:33pm

The website he gave you shows step by step how to do it.


R1 = r1/6
R2 = (-4r1 + r2) * (3/13)


x - (y/3) = - (7/6)
0 + y = 5

thats what i got

given:
+6 -2 | -7
+4 +3 | +17

(1/6)*R1 --> R1:
+1 -1/3 | -7/6
+4 +3 | + 17

R2-4R1 --> R2:
+1 -1/3 | -7/6
+0 +13/3 | +65/3

(3/13)R2 --> R2:
+1 -1/3 | -7/6
+0 +1 | +5

(1/3)R2 + R1 --> R1:
+1 +0 | +1/2
+0 +1 | +5