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Jan 9 2016 03:28pm
what are the odds of losing a 1 out of 6 21 times in a row?
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Jan 9 2016 05:04pm
(5/6)^21 ≈ 2.1737%
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Jan 9 2016 11:16pm
Quote (Nathan @ 10 Jan 2016 00:04)
(5/6)^21 ≈ 2.1737%


ty
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Jan 11 2016 10:56am
Quote (Nathan @ Jan 9 2016 07:04pm)
(5/6)^21 ≈ 2.1737%


Just to break this down... instead of just having the solution

Your odds of losing are 5 out of 6, since 1 out of 6 is a win.... hence the 5/6.... and this is repeated 21 times... This same formula can be applied in almost all statistics.
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Jan 21 2016 12:39pm
Quote (Panjos @ Jan 11 2016 11:56am)
Just to break this down... instead of just having the solution

Your odds of losing are 5 out of 6, since 1 out of 6 is a win.... hence the 5/6.... and this is repeated 21 times... This same formula can be applied in almost all statistics.


^this!
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Jan 24 2016 04:29pm
Quote (Panjos @ Jan 11 2016 04:56pm)
Just to break this down... instead of just having the solution

Your odds of losing are 5 out of 6, since 1 out of 6 is a win.... hence the 5/6.... and this is repeated 21 times... This same formula can be applied in almost all statistics.


This is indeed true for all (?) statistics, i.e. that you take the expected value for your desired result and multiply with "itself" as many times as the process is repeated. For other distributions the formula become different. This is however only true for independent processes, i.e. that if the return of a try is not dependent on other tries.
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