F(G(x)) you just need to sub in G(x) into F(x) whereever u see x
F(G(x)) = 3 - 2[-.5(x-3)] = 3 - (x-3) = x

G(F(x)) u just need to sub in F(x) into G(x) wherever u see x
G(F(x)) = -.5([3-2x] - 3) = -.5(-2x) = x

for #2 cant solve it since its not equal to anything. for #3 shuld it be F(x) = 3^x?

Question 1:
F(x) = 3 - 2x
G(x) = -(x - 3)/2

F(G(x)) means to put G(x) into all places you see x in the first equation....so

F(G(x)) = 3 - 2 * (-(x-3)/2))
F(G(x))= 3 - (-(x-3)) = X

G(F(x)) = -(3 - 2x - 3)/2
G(F(x)) = -(-2x/2) = X

Question 2:
You didn't provide an actual equation to solve, so I'm going to assume that what you gave is supposed to equal 0.

8-2e^x = 0
2e^x = 8
e^x = 4
ln(e^x) = ln(4)
x = ln(4) = 1.386

As a side note if you don't really understand ln. ln(e^x) is the same of Log base e of e^x. So, what power do you have to put on e (the base) to get e^x. You have to raise the base to x, that is why ln(e^x) = x

Question 3.
I assume you know how to graph y = 3x.

The second equation is the inverse of y = log(3x), so take the inverse: x = log(3y).

Now solve this second equation for y and graph it....

x = log(3y)
10^x = 3y
y = (10^x) / 3

This post was edited by RzChaos on Nov 10 2015 10:10pm

Shit, didn't see you had a negative sign in number 2 before the x...approach is going to be the exact same, just remember to have an additional negative sign in there, so the answer will be -1.386

This post was edited by RzChaos on Nov 10 2015 10:09pm

for question 2 its equal to 4 idk how I missed that! sorry
and ok gimme a few to comprehend these!

Ahh ok.

8 - 2e^-x = 4
2e^-x = 4
e^-x = 2
ln(e^-x) = ln(2)
-x = ln(2)
x = -ln(2)
x = -0.693

Going to bed now...will check tomorrow if you need more help.