I can only see one problem at a time so I will post the new one once it is available to me (once the previous question has been answered)
I will pay 1fg per answer unless a question is unreasonably difficult.

At a family gathering there are 100 people. There are 4 less than twice as many women as men and 6 more children as both combined. How many children are at the gathering?
57, 50, 55, or 53.

53 children

Solved it a good while ago lol
Internet died on my friends computer but I'll have more problems soon hopefully

In case you wanted work for it.

I just did it for the lols.


100 ppl

M = m

W = 2m-4

C = W + m + 6
C = (2m - 4) + m + 6
C = 3m+2

PPL = C + W + M = 100

100 = (3m + 2) + (2m-4) + m
100 = 6m - 2
102 = 6m

17 = m = M

30 = W

53 = C

At first I found x = man

x +( 2x -4 ) + ( x + 2x - 4 + 6 ) = 100
x = 17

then y = children
y = x + 2x - 4 + 6
y = 17 + 2*17 - 4 + 6
y = 53

But then the problem is stupid when you think about it, because you don't need all the information provided.
x = children (count men and women together - don't need to seperate this group)

x + ( x - 6 ) = 100
2x = 106
x = 53