A hockey player is standing on his skates on a frozen pond when an opposing player, moving with a uniform speed of 4.0 m/s, skates by with the puck. After 1.40 s, the first player makes up his mind to chase his opponent. If he accelerates uniformly at 0.14 m/s2, determine each of the following.

(a) How long does it take him to catch his opponent? (Assume the player with the puck remains in motion at constant speed.)

in meters

(b) How far has he traveled in that time?

in meters




i tried to work this out many times but just cant figure it out

first u use xi +vi + 1/2 t ^2

then quadratic equation?

Hockey player 1 and 2s distance must be the same right? that means the player who stood still caught up
distance equations are

d=4*time
d=(.5)a(t^2)

im still lost

Oh my bad, I made a mistake
I didn't even see the time in the problem.

Look,
1. both hockey players were at the same place at one point in time.
2. if the player who was standing still caught up, that means they've traveled the same distance

Write your distance equations

Distance_1 = velocity*time + 1.4*4
1.4*4 is how far he was when the other person decided to start moving.

Distance_2 =(.5)a(t^2)

Set them equal to each other.