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Sefira
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#1
Jun 2 2015 01:57pm
Have two problems that I need assistance with:
&
Convert the rectangular equation to polar form.
y^2 - 8x - 16 = 0.
If anyone is able to help, that'd be greatly appreciated, thanks.
trollen
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#2
Jun 2 2015 02:05pm
Quote (Sefira @ Jun 2 2015 07:57pm)
Have two problems that I need assistance with:
http://i.cubeupload.com/IwV3SW.png
&
Convert the rectangular equation to polar form.
y^2 - 8x - 16 = 0.
If anyone is able to help, that'd be greatly appreciated, thanks.
if x = 1 dat answer is 1 bro
Sefira
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#3
Jun 2 2015 02:25pm
I tried using the quadratic formula for the second problem, seems to be the correct approach.
Only need help on the first one now.
feanur
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#4
Jun 2 2015 03:30pm
f(x) = (1/√x - 1/√7) / ( x - 7 )
f(x) = (√7 / √(7x) - √x / √(7x) ) / ( x - 7 )
f(x) = ( √7 - √x ) / [ √(7x) * ( x - 7 ) ]
f(x) = ( √7 - √x ) / [ √(7x) * ( √x - √7 ) * ( √x + √7 ) ]
f(x) = - 1 / [√(7x) * (√x + √7) ]
Now, it should be clear that limit, as x approach 7, of f(x) is - 1 / (14√7)
Sefira
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#5
Jun 2 2015 05:19pm
Thanks
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