Need full solution if possible. Friend asked me this question but I took this class like 3 semesters ago and dont remember anything



This post was edited by VietBM on May 11 2015 12:47am

84 over pi

draw a crude penis at bottom of page

x= 940


nn tips, gl

I would have done this for free but d2jsp's moderators literally stole over 90k of fg from me because they're neckbeards so I have nothing now. I'd do it and explain it for forum gold or $$.

Lmao
I'm interested in knowing how they were able to do thisi


Meanwhile

PRAIZEALLAH

nice

Don't feel like doing the math... But looks like you're finding the volume.

S is the set of points with coordinates ( r.cost ; r.sint ; r.sint + 3 ), where (r;t) are the polar coordinates : 0<r<1 and 0<t<2.pi
dS = 2r.dr.dt

I is the integral from r = 0 to 1, from t = 0 to 2.pi, of 2.r^2.sint(r.sint + 3) = 2.r^3.(sint)^2 + 6r^2.sint
Evaluate first the integral along t :
integral of sint gives 0,
integral of (sint)^2 gives pi.

Leaving you with integral from 0 to 1 of 2.pi.r^3.

Finally, I = pi/2

This post was edited by feanur on May 15 2015 02:32am

should be dS = sqrt(2).rdr.dt

Final result must be divided by sqrt(2).