EDIT Sorry 200fg title is wrong typo...

RULES MUST BE FOLLOWED:

Please...
Do PROBLEMS on a SEPARATE PIECE OF PAPER AND SHOW ALL WORK THEN TAKE PICTURE AND UPLOAD IT HERE! (Please be neat and legible).
In order for you to get fg. First one to answer a problem gets the fg (if correct) subsequent posts will not be awarded.

or u can feel free and help out of kindness of your heart and just post

please upload by 3/11/2015 12am PST.

BELOW EACH WOULD BE 50g.
Find the derivative of the function. Simplify when possible.





BELOW EACH WOULD BE 100fg



This post was edited by cKranez on Mar 9 2015 01:58am

D)
http://postimg.org/image/mtxo3vscj/

This post was edited by TheStealthTarget on Mar 9 2015 07:32am

E)
http://postimg.org/image/r4cbzgxfn/

F)
http://postimg.org/image/a53dk7m83/

Final solution can be simplified

ty i guess the otehrs are a bit long? lol

ok for 6a i found the derivative being (2-x/x^3) how do i find the local max/min and if f is decreasing/increasing? do i set both 2-x=0 and x^3= 0 getting .....

x=0 & x=2 using these as test points to determine the increasing/ decreasing? meaning increasing from (0, infiniti) and decreasing from (-infiniti,0)

additionally to determine local max/min i just plug 0&2 back into the original equation? getting one point being that 0 would produce a divded by zero error?


This post was edited by cKranez on Mar 10 2015 07:02am

additionally for 6. theres a b part that asks for concavity/inflection points.. so i found the 2nd derivative to be (2x-6) / (x)^4

so would my concavity points be at 2x-6=0 and x^4=0 .. being x=3 / x=0 these being my test points? and points to plug into the original equation to find the y value?

giving me an inflection point : (3,0) ... only have one inflection point? since plugging in 0 would give me divided by zero error?

and Concave down: (-infiniti, 3) up:(3, infiniti)

This post was edited by cKranez on Mar 10 2015 06:56am

f'(x) = (-x + 2)/x^3

Basically to test if it's a local maximum or local minimum, try to plug in values of x and see what f(x) spits out, if the diference of the values become smaller and smaller and is increasing, it's going towards a max. If the difference of values become smaller and smaller and is decreasing, it's heading towards a minimum.

in your case it's a max

This post was edited by zyQuzA0e5esy2y on Mar 11 2015 05:36pm