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Dec 10 2014 03:07pm
Hey so I'm reviewing for my calculus final and came across this problem:



I'm having trouble how to integrate here. Here are my integrals in both orders dxdy and dydx

Int ( x=-sqrt(3)/2 to x=sqrt(3)/2, y=1/2 to y=sqrt(1-x^2) ) y^3(x^2+y^2)^(-3/2) dydx

Int ( y=1/2 to y=1, x=-sqrt(1-y^2) to x=sqrt(1-y^2) ) y^3(x^2+y^2)^(-3/2) dxdy

In both cases I am having trouble just dealing with the integrand. Can anyone help? Is it going to be a nasty trig substitution?

If the above is hard to read this is what I mean:

Member
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Dec 10 2014 03:25pm
Would be easier if you did a change of variables to polar coordinates.
x = rcosθ
y = rsinθ

|Jacobian| = r
Member
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Dec 10 2014 03:42pm
Quote (cdexswzaq @ Dec 10 2014 04:25pm)
Would be easier if you did a change of variables to polar coordinates.
x = rcosθ
y = rsinθ

|Jacobian| = r


I've never learned how to use polar coordinates in integrals
No idea what the Jacobian associated with this integral is
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Dec 10 2014 04:12pm
Quote (Bloo_Guardian @ Dec 10 2014 05:42pm)
I've never learned how to use polar coordinates in integrals
No idea what the Jacobian associated with this integral is


Haha, then there will most likely be a trig substitution in your integral :wallbash:
Member
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Dec 11 2014 02:42am
Try polar.



If you want the technical analysis, try this:

http://en.wikipedia.org/wiki/Fubinis_theorem

Never mind the above, just google "Fubinis theorem".

This post was edited by Casey on Dec 11 2014 02:46am
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