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Dec 8 2014 08:26pm
I want to know how the Ff from the 2nd line turns into Fn in the third

Also how the third line turns into the final equation that is circled. I can't figure out where the extra Fn went.

http://i.imgur.com/Sm4LDXI.jpg
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Dec 8 2014 10:22pm
Can we know more about the problem? The Ff to Fn could just be a simple error with formulas.

The third line you should be able to factor out a Fn, give me a second to upload a picture.

e; can't solve it, not sure where that static friction coefficient came into play.

This post was edited by Blizzardboy on Dec 8 2014 10:28pm
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Dec 8 2014 11:22pm
Afaik this is a centripetal force problem on an incline.

Ff is Fn * mu, but it wasn't written in the middle equations, just thrown in @ the end.

Ignore FBD in top right.
Use FBD on right side.



This post was edited by Dontrunaway on Dec 8 2014 11:35pm
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Dec 9 2014 12:36am
Quote (Whalefood @ Dec 8 2014 09:26pm)
I want to know how the Ff from the 2nd line turns into Fn in the third

Also how the third line turns into the final equation that is circled. I can't figure out where the extra Fn went.

http://i.imgur.com/Sm4LDXI.jpg



Pretty simple solve... Factor F_n out on right side and solve for it by dividing by (sin(19.4)+cos(19.4)) to get solution.
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Dec 9 2014 12:46am
Quote (Xx Shin3d0wn xX @ Dec 9 2014 12:36am)
Pretty simple solve... Factor F_n out on right side and solve for it by dividing by (sin(19.4)+cos(19.4)) to get solution.


Can't forget mu.
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Dec 9 2014 11:17am
Quote (Dontrunaway @ Dec 9 2014 01:46am)
Can't forget mu.



Indeed forgot to type that in :0 typing math on phone made me miss that one lol but you had a nice picture of solution for him already, was just trying to explain steps for him.
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