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d2jsp Forums > Off-Topic > General Chat > Homework Help > Calculating [h+] (chemistry) > (chemistry)
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#1
Nov 21 2014 08:37am
okay so I got this problem

I have to calculate [H+] in CH3OOH -> CH3OO- + H+
the Ka = 1,8 * 10^(-5)

*edit I've been doing this wrong


CH3OOH is 0,5M




is [H+] maybe just -log(1,8*10^(-5) ?

This post was edited by twiiztedacer on Nov 21 2014 08:58am
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#2
Nov 21 2014 09:32am
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#3
Nov 22 2014 07:35pm
if u have anymore questions give me a pm
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