http://upload.wikimedia.org/math/5/0/f/50f9cad0c149bd3fe30446a17b834884.png
http://en.wikipedia.org/wiki/Orbital_periodmu = GM, which you equivilate with the Earth's value because the problem assumes the Sun is the same sun so you can remove it, along with 2 pi
T is in seconds, and earth takes 1 year
T1/T2 = sqrt(Eartha^3)/sqrt(a^3) solve for a^3
1/33 = 5.7863x10^16 / sqrt(a^3)
sqrt(a^3) = 1.9095x10^18
a = 1.5391x10^12thank you I appreciate it.