Any help on understanding this concept would be appreciated.

I am not understanding how this is working.

How does the voltage across the resistor change less when the resistor is changed when using a bleeder resistor?

This post was edited by ROM on Oct 21 2014 05:18pm

*electric

So, I was working it out on paper and I kind of see what its happening.

I am using the 20v power supply.

Having a 333 ohm resistor in series with a 1k ohm resistor, yields 15v across the 1k ohm resistor.
Changing the 1k ohm resistor to 520 ohm yields 12.19v across the 520 ohm resistor.
Voltage Regulation = 18.73%

Adding a bleeder resistor of 500 ohm, and resistor in series of 111 ohm.
Having a resistor of 1k ohm, I get the 15v.
Changing the 1k ohm resistor to 520 ohm, I get 14v.
Voltage Regulation = 6.66%

So, I am understanding I guess but kind of looking for it a little better explained.
Sorry if my thoughts make no sense, I am confused myself.

This post was edited by ROM on Oct 21 2014 06:49pm

because you have less voltage drop to work with.

This is happening because changing the resistor in paralel has a lesser effect on total resistance then when it was in series, right?

What is a practical application just for me knowledge, where resistance would change but voltage needs to stay the same?

This post was edited by ROM on Oct 22 2014 04:56am

rereading what you did , it is not very systematic or clear.
adding a resistor in parallel across the voltage source will not change the voltage the voltages across the other resistors you have in series to the source. don't drop the total resistance too low for the sake of your power supply

This post was edited by saber_x3 on Oct 22 2014 09:48am

Total Resistance will only have an effect of the current drawn by the power supply i.e. this:



He's right in the idea that adding that bleeder resistor across the output of the voltage supply will do nothing in regards to the voltage drop. I could help some more if I fully understood your question. From what I can tell, its a simple application of Kirchhoff's Voltage Law.