How do I express 2^5 in base e

log base 2 (e) =5

feeling like its more complicated than that though

CAN YOU rephrase your question

It just says express 2^5 using base e.
But log base 2 (e) = 5 seems way to simple compared to the other questions/answers

ah so then it would be:

e^(5*ln2) or exp(5*ln2)

the e and ln will cancel out and by the power rule for logarithms, 5*ln2 = ln2^5

would really appreciate any fg donations for help (i can help you in the future as well)
if not it's cool...just that im in a bit of clinch right now

This post was edited by JDota72 on Sep 19 2014 08:32pm

this is just a simple algebra problem.

2^5 = e^x

ln(2^5) = ln(e^x)

ln(2^5) = x