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Sep 17 2014 06:01pm
Hey so I'm having trouble with this problem even though it should be pretty simple ...



Just going to use the notation for the rows and columns of matrices as [ a11 a12 a21 a22 ]

I think I have to do something where I have scalar values k, such that

k1*[ a 0 0 0 ] + k2*[ 0 b b 0 ] +k3*[ 0 0 0 c ] = 0 ?

And then I will prove that this spans all matrices [ a b b c ] ? Or something like that I'm not sure really I'm kind of lost
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Sep 17 2014 06:40pm
Quote
think I have to do something where I have scalar values k, such that

k1*[ a 0 0 0 ] + k2*[ 0 b b 0 ] +k3*[ 0 0 0 c ] = 0 ?

And then I will prove that this spans all matrices [ a b b c ] ? Or something like that I'm not sure really I'm kind of lost


it's been a while, but i think you just have to show they span every matrix in your domain.

so:

k1*[ 1 0, 0 0 ] + k2*[ 0 1, 1 0 ] +k3*[ 0 0, 0 1 ] = [a b, b c]

then a = k1, b = k2, c = k3

could be wrong though.

maybe you have to show they're linearly independent? not sure

This post was edited by carteblanche on Sep 17 2014 06:40pm
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Sep 17 2014 07:09pm
So a = k1, b = k2, c = k3 shows that the given matrices span every matrix in the vectorspace?
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Sep 18 2014 07:42am
you must prove that every single 2x2 symetric matrix can be written unambiguously as a linear combination of those 3 matrix
what carteblanche wrote is correct
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Sep 18 2014 10:35am
Quote (HbSoe @ Sep 18 2014 02:42pm)
you must prove that every single 2x2 symetric matrix can be written unambiguously as a linear combination of those 3 matrix
what carteblanche wrote is correct


Is he asked to prove that those 3 matrices form a base of the subspace of symmetric matrices, or only that they generate it ?
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Sep 20 2014 08:15pm
the span is ALL the linear combination of your matrices. to show the linear combinations you have

S =a1[1 0;0 0] + a2 [0 0; 0 1]+a3 [0 1;1 0] where S is the span

S = [a1 a3; a3 a2]
the matrix above shows all the linear combinations. now to show that it spans all the SYMMETRIC 2x2 matrices you have to show the transpose of S is S
To compute the transpose you just have to swap the rows into columns.

Edit: you should end up with [a1 a3;a3 a2]^T = [a1 a3;a3 a2]

This post was edited by cdexswzaq on Sep 20 2014 08:16pm
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