Here is the problem.



As you can see, the answer I chose is wrong. Explanations would be cool but just an answer is fine, thanks.

First of all:

Derivative of Position = Velocity
Derivative of Velocity = Acceleration
Derivative of Acceleration = Jerk

First I look at function "a". Here you can see that the derivative = 0 at two different times (The times when the slope changes between positive and negative). You can see that none of the other graphs have two points that = 0 at these two times so "a" must be jerk.

Now that we know "a" is jerk, we can take the integral of it to find the acceleration curve. The acceleration curve should have a positive slope up until the time "a" crosses the x-axis, after than it will have a negative slope for the rest of the figure. This means "b" has to be acceleration.

Now take the integral of "b" to find velocity. Velocity should be increasing until the time "b" crosses the x-axis at which point it will begin to decrease. This means "c" has to be velocity.

D is the only function left so it is position. Or you can take the integral of "d" and see that it is north of x=0 for it's entirety indicating that position is the function which is always increasing (d)

Realizing now that you very well may not know about integrals so....

You can determine that "a" is jerk as described in my previous post, since none of the other graphs represent its derivative.
You can then look at the point where "a" crosses the x-axis, at this point acceleration should have a derivative of 0. This means that "b" has to be acceleration.
Now look at the point where "b" crosses the x-axis, at this point velocity should have a derivative of 0. This means that "c" has to be velocity

Again that means "d" has to be position.

This post was edited by RzChaos on Sep 14 2014 02:32pm

Thank you. Everything you said made sense, I just had trouble seeing it.