cant figure out the last one

Ive tried calculating it as a series, in parallel, and a few other ways but i cant get it

This post was edited by Wacko on Sep 7 2014 05:47pm

C1 is parallel with C3
as with all capacitors they are opposite of resistors

instead of using

c1 x c3 (Divided By) c1 + c3

like you would with parallel resistors

just add them together.

Eh? No.
C1 is parallel to the series combination of C2 and C3.

http://www.electronics-tutorials.ws/capacitor/cap_7.html


Given C1= 192 pF

You already found the voltage of C1 to be 6

C1=Q/V ---------> Q = C1*V------->Q = 192*6=1152 pC

This post was edited by DynastyFury on Sep 23 2014 05:37pm