Two 52.0 x 10-9 C point charges are located on the x axis. One is at x = 0.25 m, and the other at x = - 0.25 m.
a) A third identical charge is placed on the y axis at y = 0.25 m. Find the magnitude of the force acting on this third charge? Answer in Newtons.
Now the third identical charge is placed on the y axis at y = 2 x 0.25 m. Find the magnitude of the force acting on this third charge? Answer in Newtons
So im not getting the right answer on A. Lets call the charge at x = -0.25m Q1 and the point at x = .25m Q2. The point at y = .25m is Q3. The angle formed by these points would be 45 degrees. So breaking it down the X components would cancel right? My y components would be the electric fields of each charge acting on Q3 multiplied by sin(45) correct? So F(Q1) = F(Q2) = kQ1Q3/(distance formula)^2 right?
This post was edited by Wacko on Aug 31 2014 10:18am