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Jul 15 2014 10:11pm
The answer must equal 4856

I'm not good with math, I just need need a problem that equals 4856 that looks complicated. (I gotta screw with one of my guys for something)
And please show work(or anti-work I guess)
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Jul 15 2014 10:54pm
Quote (kevinholland10 @ Jul 15 2014 10:11pm)
The answer must equal 4856

I'm not good with math, I just need need a problem that equals 4856 that looks complicated. (I gotta screw with one of my guys for something)
And please show work(or anti-work I guess)



1.0133*10^179 = [(x+.01)^(x/100)] + x^3.21 - pi*x

The solution to that equation is 4856, there are an infinite # of equations that can equal that number.

y = f(x)
y(4856) = f(4856)
0 = f(x) - y(4856)

The root(s) of the equation will make this expression true.
In this example f(x) is [(x+.01)^(x/100)] + x^3.21 - pi*x and y(4856) is f(x) where x=4856. You just create a function, which has a root of the desired #, which you have an infinite choice of. Because you gave me the solution, I plugged 4856 into my arbitrary function and subtracted that number from f(x).

This post was edited by nobrow on Jul 15 2014 10:57pm
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Jul 15 2014 11:55pm
Quote (nobrow @ 15 Jul 2014 23:54)
1.0133*10^179 = [(x+.01)^(x/100)] + x^3.21 - pi*x

The solution to that equation is 4856, there are an infinite # of equations that can equal that number.

y = f(x)
y(4856) = f(4856)
0 = f(x) - y(4856)

The root(s) of the equation will make this expression true.
In this example f(x) is [(x+.01)^(x/100)] + x^3.21 - pi*x and y(4856) is f(x) where x=4856. You just create a function, which has a root of the desired #, which you have an infinite choice of. Because you gave me the solution, I plugged 4856 into my arbitrary function and subtracted that number from f(x).


Sick
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Jul 16 2014 04:29am
Quote (nobrow @ Jul 16 2014 05:54am)
1.0133*10^179 = [(x+.01)^(x/100)] + x^3.21 - pi*x

The solution to that equation is 4856, there are an infinite # of equations that can equal that number.

y = f(x)
y(4856) = f(4856)
0 = f(x) - y(4856)

The root(s) of the equation will make this expression true.
In this example f(x) is [(x+.01)^(x/100)] + x^3.21 - pi*x and y(4856) is f(x) where x=4856. You just create a function, which has a root of the desired #, which you have an infinite choice of. Because you gave me the solution, I plugged 4856 into my arbitrary function and subtracted that number from f(x).


Doesn't work like that... The solution might be very closed to 4856, but cannot be exactly 4856.

Quote (kevinholland10 @ Jul 16 2014 05:11am)
The answer must equal 4856

I'm not good with math, I just need need a problem that equals 4856 that looks complicated. (I gotta screw with one of my guys for something)
And please show work(or anti-work I guess)


What about :

Find the lowest natural numbers x and y such that :
14430*x = 1 + 15323*y

?
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Jul 20 2014 01:07am
Quote (kevinholland10 @ Jul 15 2014 09:11pm)
The answer must equal 4856

I'm not good with math, I just need need a problem that equals 4856 that looks complicated. (I gotta screw with one of my guys for something)
And please show work(or anti-work I guess)


Just work backwards? Start with 4856 then do things in that same order so it can be fixed... Like
4856-1000/(5x4)=4806 but add in more confusing things like logs and other stuff :p
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Jul 20 2014 03:32pm
Quote (nobrow @ Jul 16 2014 12:54am)
1.0133*10^179 = [(x+.01)^(x/100)] + x^3.21 - pi*x

The solution to that equation is 4856, there are an infinite # of equations that can equal that number.

y = f(x)
y(4856) = f(4856)
0 = f(x) - y(4856)

The root(s) of the equation will make this expression true.
In this example f(x) is [(x+.01)^(x/100)] + x^3.21 - pi*x and y(4856) is f(x) where x=4856. You just create a function, which has a root of the desired #, which you have an infinite choice of. Because you gave me the solution, I plugged 4856 into my arbitrary function and subtracted that number from f(x).


how does pi*x ever become rational in your equation? i think you'll need some sort of floor/ceiling/round
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Jul 20 2014 10:04pm
Quote (carteblanche @ Jul 20 2014 03:32pm)
how does pi*x ever become rational in your equation? i think you'll need some sort of floor/ceiling/round


It doesn't have to be, the LHS of the equation will be an irrational #. I am an engineer not a mathematician
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Jul 20 2014 10:53pm
Quote (nobrow @ Jul 21 2014 12:04am)
It doesn't have to be, the LHS of the equation will be an irrational #. I am an engineer not a mathematician


what are you talking about?

1.0133*10^179 = [(x+.01)^(x/100)] + x^3.21 - pi*x

1.0133*10^179 is an integer, thus rational. it's 10133 followed by 175 zeros. i'm guessing whatever calculator you used rounded for scientific notation.
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