Quote (nlin @ Jun 22 2014 03:04am)

Are you given the mass of the block?

Quote (nlin @ Jun 22 2014 08:38pm)

Drew a beautiful paint diagram

http://i.imgur.com/qEdE23P.png


I break up the force due to gravity into two components: (right half of the image)

F(x) = mg sin theta
F(y) = mg cos theta

Memorizing these simplified every incline plane problem for me


As everyone has mentioned, Uniform speed means no acceleration
a = 0

Sum of forces = ma
Sum of forces = 0

F(x) - F(fr) = 0
F(x) = F(fr)

you know that F(fr) = mu(Fn)

F(x) = mu(Fn)
mg sin theta = mu(Fn)
Mu = (mg sin theta) / (Fn)
Mu = (mg sin theta) / (mg cos theta)
Mu = sin 16 / cos 16

Quote (nlin @ Jun 22 2014 12:38pm)

Drew a beautiful paint diagram

http://i.imgur.com/qEdE23P.png


I break up the force due to gravity into two components: (right half of the image)

F(x) = mg sin theta
F(y) = mg cos theta

Memorizing these simplified every incline plane problem for me


As everyone has mentioned, Uniform speed means no acceleration
a = 0

Sum of forces = ma
Sum of forces = 0

F(x) - F(fr) = 0
F(x) = F(fr)

you know that F(fr) = mu(Fn)

F(x) = mu(Fn)
mg sin theta = mu(Fn)
Mu = (mg sin theta) / (Fn)
Mu = (mg sin theta) / (mg cos theta)
Mu = sin 16 / cos 16
















In this step I substituted (mg cos theta) or the Fy component of gravity. I got this from Sum of forces in the Y direction (because the box isn't moving vertically) = 0

(Again, the box is not moving or accelerating in the Y direction so a = 0)

In the second picture imagine the Normal Force is drawn in (normal force always perpendicular to plane)

So then F(n) - F(y) = 0
F(n) = F(y)