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Jun 16 2014 12:47pm
must show work and be done by 415pm est



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Jun 16 2014 12:58pm
sorry for the size. 200 fg a problem. show work, picture preferred.
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Jun 16 2014 01:07pm
I pm'd you a full solution to the last question. I am having troubles reading the other problems as every time I try to make it bigger it gets all blurry
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Jun 16 2014 02:14pm
Quote (Minty @ Jun 16 2014 12:07pm)
I pm'd you a full solution to the last question. I am having troubles reading the other problems as every time I try to make it bigger it gets all blurry


thanks sending fg for that
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Jun 16 2014 02:21pm
comment if you need me to type out a problem. new deadline 515
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Jun 16 2014 02:30pm
#7 above 8 which was a completed equation is
use synthetic division to find the zeroes of f(x)=2x^3-5x^2+x+2
a. {2,-2,3}
b.{1,-1,2}
c.1,2,-1/2)
d.{0,1,2}
e. none
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Jun 16 2014 02:48pm
Quote (remedyz528 @ Jun 16 2014 02:30pm)
#7 above 8 which was a completed equation is
use synthetic division to find the zeroes of f(x)=2x^3-5x^2+x+2
a. {2,-2,3}
b.{1,-1,2}
c.1,2,-1/2)
d.{0,1,2}
e. none



The equation f(x) = 2x^3-5x^2+x+2 can also be written as (x-2)(x-1)(2x+1) = 0 and thus the zeroes of the equation are 2,1,-1/2.
/e to determine if these are true zeroes (x=2,1,-1/2) using synthetic division, set up the synthetic division and see if the remainder is zero. If the remainder is zero then (x=2,1,-1/2) are true zeroes. If you need help setting up synthetic division pm me and I can show you/set it up for you.

This post was edited by Minty on Jun 16 2014 02:51pm
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