I took an online test today, I passed the test but there were these
4 problems that I didn't know the answer or how to solve.

If you could give me the correct answers and show to me how you got them, I would be very appreciative.



I've got 100fg to the first person who can show me how this is done correctly. (This is to the first person that helps me, not necessarily the first in this thread.)
I want to be able to understand and complete these types of problems.

the first one x=1/15a & a=/=0

*divide both sides by 3a
3ax/3a = 1/5/3a

simplify* x= 1/(3*5)a
x=1/15a and clearly a=/=0

the graphing one you need to pretty much realize what "rate of change" and " y intercept" are

rate of change is slope (the number in front of the variable x)
the y intercept is just the lonely number all you do it compared the two the equation for the graph (function first you need to realize its linear and the rate of change is rise/run and the y intercept is where it cross the y axis so

it rises 1
runs 2
its slope is 1/2x

the function crosses the y axis at (0,-2)
so the y intercept is -2

so the equation is y=1/2x - 2

then you just compare the numbers and its obvious


the line the passes through points you need to know the equation
y=mx+b

first solve for m using
m=y2-y1 / x2- x1

you get -2-1/6-0 which equals -1/2 so now you got your slope
-1/2x

to find b fill in your points for x and y and solve for b just like you would
y=-1/2x + b lets use (0,1)
so at x=0 and y=1 we get
1=(-1/2 * 0) = b
1=b
so we get b=1
put that together we get
y=-1/2x + 1

for the table problem you are just asked to put into numbers that make a function you don't need an equation you pretty much just cant repeat the pairs that are in the table and you cant have x going to two different y values so put like

8 in for x
9 in for y

think about it this way when you picture a graph of a function do you picture like lines on top of each other? no you probably think of one squiggly line

This post was edited by brigadier on May 9 2014 05:28pm