(√3x+3) = (√x+2) + (√x-1)


would this be correct?

3x+3 = (√x+2)² + 2(√x+2)(√x-1) + (√x-1)² and from here on just the way u do a double √ ?

My moms is a college math prof I will ask her when I talk to her in like an hour.

This post was edited by bigbenbenn on May 7 2014 11:51am

As an example -x = 2 is not the same as x^2 = 4, so I think you cant just do that without checking that you're not adding solutions to the equation by squaring both sides. Could just be saying crap though someone correct me plz

(√3x+3) = (√x+2) + (√x-1)

or

√(3x+3) = √(x+2) + √(x-1)

?

I think he means 2 considering he squared

3 sqrt(3) sqrt(x) = 2 (sqrt(x)-1) sqrt(x)

Then :

√(3x+3) = √(x+2) + √(x-1)

Notice that the expression exists only for x greater than or equal to 1, because of the term √(x-1).

Square both sides :

3x + 3 = x+2 + x-1 + 2√((x+2)(x-1))

Cancel out some terms :

x + 2 = 2√((x+2)(x-1))

Square again :

x² + 4x + 4 = 4 (x+2)(x-1) = 4x² + 4x - 8

Cancel out :

3x² = 12

x² = 4

x = 2 or x = -2

Eliminate x = -2 (see above)

Finally x = 2.