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Apr 27 2014 07:57pm
So I have:

lim as u-->inf of (-3u^3-6u+6)/sqrt(2-u+6u^2+4u^2)

I know how to work it out, and when I do, I come up with the a result of -inf. The answer key I have says it's +inf.
The reasoning I have is when you take out u^3/u^2, you can simplify to get inf*(-3/2). Shouldn't that make the answer -inf? It's possible my professor messed up and forgot to put the negative sign. Thanks!
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Apr 27 2014 08:05pm
Quote (Barcelona1011 @ Apr 27 2014 09:57pm)
So I have:

lim as u-->inf of (-3u^3-6u+6)/sqrt(2-u+6u^2+4u^2)

I know how to work it out, and when I do, I come up with the a result of -inf.  The answer key I have says it's +inf.
The reasoning I have is when you take out u^3/u^2, you can simplify to get inf*(-3/2).  Shouldn't that make the answer -inf?  It's possible my professor messed up and forgot to put the negative sign.  Thanks!


sqrt can be positive or negative.

easy way to test it yourself is to pick a few values for u. eg 10, 100, 10000000. and see what you get.
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Apr 27 2014 08:17pm
going towards infinity you can just look at the highest powers as a first step to see if that gives you the result
in your case it is -3u^3/srqt(10u^2) which comes down to -u^3/sqrt(u^2)
since it would be standard to use the positive root rather than the negative one, i would have given the same answer you did
but as 'cartblanche' said, the root can be plus or minus - just wondering why your professor picked the negative one
btw, the test proposed by 'cartblanche' does not really help
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Apr 27 2014 08:32pm
Completely forgot about the sqrt being positive or negative there lol. Thanks!
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Apr 27 2014 08:35pm
The reason I was confused is because this is the key he gave

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Apr 28 2014 04:51am
" sqrt(X) " always denotes the positive root (when it exists) of the equation A² = X.

You were right in the first place.

When using the factorisation (previous post) :

- the first term (u^3 / u²) simplifies as u, and its limit is either +infinity (as u approaches +infinity) or - infinity (as u approaches - infinity).

- the numerator always tends to -3 ( as u approaches + or - infinity)

- the denominator always tends to 2 ( as u approaches + or - infinity).

As a result, the given quantity tends to - infinity as u approaches + infinity, and tends to + infinity as u approaches - infinity.

Notice that the way the problem is asked is unclear ( " u -> infinity " without saying if it is " u -> + infinity " or " u -> - infinity").

Also notice that, whereas the first form exists for any real number u, the factorized form doesn't stand when u = 0 (but there's no problem while considering the limits towards infinity).
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Apr 28 2014 05:10am
Quote (Barcelona1011 @ 28 Apr 2014 02:35)
The reason I was confused is because this is the key he gave
http://i.imgur.com/wHd11F3.png


if he gave you this picture, he just has been slack to ignore the -3/2 (especially the "-")
so maybe he should go back to school B)
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