Quote (Barcelona1011 @ Apr 27 2014 09:57pm)
So I have:
lim as u-->inf of (-3u^3-6u+6)/sqrt(2-u+6u^2+4u^2)
I know how to work it out, and when I do, I come up with the a result of -inf. The answer key I have says it's +inf.
The reasoning I have is when you take out u^3/u^2, you can simplify to get inf*(-3/2). Shouldn't that make the answer -inf? It's possible my professor messed up and forgot to put the negative sign. Thanks!
sqrt can be positive
or negative.
easy way to test it yourself is to pick a few values for u. eg 10, 100, 10000000. and see what you get.