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#1
Apr 25 2014 11:39pm
so my cousin is in the math team (7th grade) and he was asking me for help on one of his problems but I dont know how to solve

Code
For what positive integer n does 3n^3 + 3n^2 + 4n = n^n


anyone know how to do this?
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#2
Apr 26 2014 12:28am
first change to 3*(n^3+n^2+n)+n = n^n
notice that n^3 < n^3+n^2+n < n^4 for n>1
so let's make an educated guess and pick n=4, and hurray

3*(64+16+4) + 4 = 3*84 + 4 = 256
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