http://gyazo.com/3de77dc600f345445538e65fe34a53bc

How I was taught.. pretty sure that's how it works out

other one
http://gyazo.com/40acbdf0915c8eeeaff366dfe7fb74d7

This post was edited by XxRadiationx on Apr 24 2014 06:12pm

Wow... thanks dude. Like the first reply, and it helped me so much. Maybe that was just super easy, regardless... thanks a lot!

Like it makes sense on the second question to square both sides to get rid of the square root, I just didn't know when to use that.

the natural log (ln) has a base of the number "e".

to solve ln(3x)=8.2
set up an algebraic equation: e^8.2 = 3x
next, divide both sides by 3 so: (e^8.2)/3 = x

same procedure for the second problem:
e^2 = sqrt(x+1)
squaring both sides: e^4 = x+1
e^4 - 1= x

This post was edited by JDota72 on Apr 24 2014 06:24pm

Yeah, exactly how it should be too. I'll send some fg out to you both. Thanks guys.

Got another if any of you are still reading this!

ln x - ln 5 = 4 (both natural logs, natural log x minus natural log 5) I know division is involved, just don't know that I am correct!

by the property of logs, they can be combined:

ln a - ln b = ln (a/b)

So using the above:

ln (x/5) = 4

Raise both sides to the e power:

(x/5) = e^4

Then multiply both side by 5 to get x by itself:

x = 5e^4

ln x - ln 5 = ln(x/5)

Perfect! And you sound like a wizard... haha. Thanks a lot sir!