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#1
Apr 16 2014 09:58am
Find the equation of the line tangent to the graph of
x^2+4x^2y^3+y^2 = 21 at (2; 1).

e/ would really like to know the process. this is a review for my exam, so the answer isn't as important as knowing how you get the answer.

This post was edited by Barcelona1011 on Apr 16 2014 09:59am
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#2
Apr 16 2014 10:45am

I won't bother finishing, but just plug in your x and y values into the derivative and you will get the slope of the tangent line at that point. Now you will have the slope of the tangent line, and a point on the line; which is enough to write its equation with the point-slope formula.
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#3
Apr 16 2014 10:46am
Quote (Azrad @ Apr 16 2014 11:45am)
http://s15.postimg.org/fv4yhxekr/imp.png
I won't bother finishing, but just plug in your x and y values into the derivative and you will get the slope of the tangent line at that point. Now you will have the slope of the tangent line, and a point on the line; which is enough to write its equation with the point-slope formula.


:hail: thank you so much.
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#4
Apr 16 2014 10:47am
if your having trouble, concentrate on lines 8 through 10 at first. When you understand that, you'll understand 4 though 7.
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#5
Apr 16 2014 10:53am
Quote (Azrad @ Apr 16 2014 11:47am)
if your having trouble, concentrate on lines 8 through 10 at first. When you understand that, you'll understand 4 though 7.


ok. thanks a ton.
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