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> Graph Of Sec X/2
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fingerling
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#1
Mar 15 2014 04:04pm
graph two periods for the secant function:
y= sec x/2
the asymptotes should be -pi/2 pi/2 pi 2pi 3pi
the points are as shown
what did i do wrong can someone tell me correct answer
This post was edited by fingerling on Mar 15 2014 04:06pm
saber_x3
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#2
Mar 15 2014 06:09pm
you should know something is wrong when you have different periods
-pi/2 to pi/2 , pi
pi/2 to pi , pi/2
pi to 2pi , pi
2pi to 3pi , pi
sec(x) is this
yours is sec(x/2) , , the divided by 2 means it takes twice the x
This post was edited by saber_x3 on Mar 15 2014 06:10pm
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