Its graded on accuracy. It's a maple assignment.

I dunno how to do this :(,

This post was edited by desertwolf on Mar 11 2014 06:41pm

you have been given the equation that describes the rocket's position.

a. projectile hits ground at s(t)=0 , position =0
velocity is derivative of position, find, s'(t) , =velocity(t), velocity function

b. find the parabola's peak

c. acceleration is the derivative of velocity, find s''(t) , or velocity'(t)

d. s(t)=750 will give you time( take first value), for when the rocket is 750 feet

e. look at velocity function

For A...
Do I take the derivative of s first, and then try to make it equal 0?

part a ask for 2 things, 2 things answered by 2 separate equations

you have been given the position equation, position equation answers position and timed related questions.

velocity equation answers velocity and time related questions
to get velocity, you must take the derivative of the position

500 feet/sec sound about right? for speed*

This post was edited by desertwolf on Mar 11 2014 07:26pm

yes, about 503ft/s